9.1.7 Checkerboard V2 Codehs Jun 2026

The complete logic relies on the mathematical property that alternating squares in a grid always have a sum of indices that switches between even and odd. ✅ Final Result

/* This program draws a full checkerboard on the screen. * It uses a constant for square size to make it dynamic. */ var SQUARE_SIZE = 40; function start() // Calculate how many rows and columns fit on the screen var rows = getHeight() / SQUARE_SIZE; var cols = getWidth() / SQUARE_SIZE; for(var r = 0; r < rows; r++) for(var c = 0; c < cols; c++) drawSquare(r, c); function drawSquare(row, col) var x = col * SQUARE_SIZE; var y = row * SQUARE_SIZE; var rect = new Rectangle(SQUARE_SIZE, SQUARE_SIZE); rect.setPosition(x, y); // The magic logic: if the sum of row and col is even, it's red if((row + col) % 2 == 0) rect.setColor(Color.red); else rect.setColor(Color.black); add(rect); Use code with caution. Copied to clipboard Pro-Tips for Success

Row 0: B W B W B W B W Row 1: W B W B W B W B Row 2: B W B W B W B W … 9.1.7 Checkerboard V2 Codehs

if ((row + col) % 2 == 0) square.setFillColor(Color.RED); else square.setFillColor(Color.BLACK);

The 9.1.7 Checkerboard V2 assignment is a fantastic milestone in learning computer science. It transitions you from thinking about linear data (1D arrays) to thinking about coordinate planes and spatial structures. By leveraging the coordinate sum rule ( row + col ), you can solve this puzzle with just a few lines of elegant code. The complete logic relies on the mathematical property

Since I don't have access to your specific instance of the problem (which usually involves a specific width, height, or starting color), I will provide the used to solve this problem in Python. This logic works for any version of the problem.

The specific requirement for "V2" is usually the dynamic coloring logic. */ var SQUARE_SIZE = 40; function start() //

function draw() for (var row = 0; row < 8; row++) for (var col = 0; col < 8; col++) if ((row + col) % 2 == 0) fill(0, 0, 0); // black else fill(255, 255, 255); // white

This article will break down the problem, explore the common pitfalls, provide step-by-step solutions in both Java (Console/Graphics) and JavaScript (Web Graphics), and explain the underlying principles so you can truly master the concept.